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aggregator

WordNet (r) 3.0 (2006) (WordNet)

aggregator
n 1: a person who collects things [synonym: {collector},
{aggregator}]

The Collaborative International Dictionary of English v.0.48 (gcide)

Aggregator \Ag"gre*ga`tor\, n.
One who aggregates.
[1913 Webster]

The Free On-line Dictionary of Computing (foldoc)

A program for watching for new content at
user-specified {RSS} feeds.

An example is {BottomFeeder}.

{(http://directory.google.com/Top/Reference/Libraries/Library_and_Information_Science/Technical_Services/Cataloguing/Metadata/RDF/Applications/RSS/News_Readers/)}.

(2003-09-29)

请选择你想看的字典辞典：

单词	字典	翻译
Aggregator	查看　Aggregator　在百度字典中的解释	百度英翻中〔查看〕
Aggregator	查看　Aggregator　在Google字典中的解释	Google英翻中〔查看〕
Aggregator	查看　Aggregator　在Yahoo字典中的解释	Yahoo英翻中〔查看〕

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英文字典中文字典相关资料:

Aggregator without any group by
What can be the scenario where I can use aggregator transformation without using any group by on any of the port For ex consdier ID SAL 1 1000 2 2000 3 3000 4 4000 How can I calculate count (*) without using group by clause in aggregator transformation ? I need to use aggregator transformation only Any help would be highly appreciated
How to get row number for 0 by using Aggregator for null input row
I assume aggregator should get some value default value for 0, or in next transformation Expression, I can set default value 0 for this total number However, it seems the result always is the row number from cache
Aggregator does not work properly - network. informatica. com
Aggregator does not work properly We have faced issue with aggregator transformation (using sum on a field having 2 decimal values), and it truncates So we end up with difference of 0 01, compare to database simple SQL aggregation query for SUM ()
What are Transformation caches in IDMC’s Cloud Data Integration?
For Aggregator, Joiner, Lookup, and Rank transformations, Data Integration creates index and data cache files to run the transformation For Sorter transformations, Data Integration creates one sorter cache file
) How to return First Last record via one Aggregator Transformation . . .
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how to count distinct - Informatica
Hi Gurus, I want to count distinct values for one column group by PK can any body show me how to achive this in INFA I can use select count (disitnct) in query, but just wondering if there is any easy way in Informatica Thanks in advance
Union Transformation - Union (Not Union All)
I think we can use Aggregator transformation with group by on all the columns to remove duplicates after union transformation The Union transformation does not remove duplicate rows To remove duplicate rows, you must add another transformation such as a Router or Filter transformation
i want to load employee details who are getting max and min sal from . . .
Connect two aggregator transformations to the source qualifier Connect empno,sal,deptno to both the aggregators Group by deptno and get min and max sal in the respective aggregator Connect the output of both the aggregators to the union transformation Connect a sorter transformation right after union and subsequent output of both source qualifier and union is connected to joiner Join
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